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15. Dynamically Creating Classes with type

By Bernd Klein. Last modified: 07 Dec 2023.

Behind the scenes: Relationship between Class and type

cogwheels or behind the scenes

In this chapter of our tutorial, we will provide you with a deeper insight into the magic happening behind the scenes, when we are defining a class or creating an instance of a class. You may ask yourself: "Do I really have to learn theses additional details on object oriented programming in Python?" Most probably not, or you belong to the few people who design classes at a very advanced level.

First, we will concentrate on the relationship between type and class. While defining classes so far, you may have asked yourself, what is happening "behind the lines". We have already seen, that applying "type" to an object returns the class of which the object is an instance of:

x = [4, 5, 9]
y = "Hello"
print(type(x), type(y))

OUTPUT:

<class 'list'> <class 'str'>

If you apply type on the name of a class itself, you get the class "type" returned.

print(type(list), type(str))

OUTPUT:

<class 'type'> <class 'type'>

This is similar to applying type on type(x) and type(y):

x = [4, 5, 9]
y = "Hello"
print(type(x), type(y))
print(type(type(x)), type(type(y)))

OUTPUT:

<class 'list'> <class 'str'>
<class 'type'> <class 'type'>

A user-defined class (or the class "object") is an instance of the class "type". So, we can see, that classes are created from type. In Python3 there is no difference between "classes" and "types". They are in most cases used as synonyms.

The fact that classes are instances of a class "type" allows us to program metaclasses. We can create classes, which inherit from the class "type". So, a metaclass is a subclass of the class "type".

Instead of only one argument, type can be called with three parameters:

type(classname, superclasses, attributes_dict)

If type is called with three arguments, it will return a new type object. This provides us with a dynamic form of the class statement.

Let's have a look at a simple class definition:

class A:
    pass

x = A()
print(type(x))

OUTPUT:

<class '__main__.A'>

We can use "type" for the previous class defintion as well:

A = type("A", (), {})
x = A()
print(type(x))

OUTPUT:

<class '__main__.A'>

Generally speaking, this means, that we can define a class A with

type(classname, superclasses, attributedict)

When we call "type", the call method of type is called. The call method runs two other methods: new and init:

type.__new__(typeclass, classname, superclasses, attributedict)

type.__init__(cls, classname, superclasses, attributedict)

The new method creates and returns the new class object, and after this, the init method initializes the newly created object.

class Robot:

    counter = 0

    def __init__(self, name):
        self.name = name

    def sayHello(self):
        return "Hi, I am " + self.name


def Rob_init(self, name):
    self.name = name

Robot2 = type("Robot2", 
              (), 
              {"counter":0, 
               "__init__": Rob_init,
               "sayHello": lambda self: "Hi, I am " + self.name})

x = Robot2("Marvin")
print(x.name)
print(x.sayHello())

y = Robot("Marvin")
print(y.name)
print(y.sayHello())

print(x.__dict__)
print(y.__dict__)

OUTPUT:

Marvin
Hi, I am Marvin
Marvin
Hi, I am Marvin
{'name': 'Marvin'}
{'name': 'Marvin'}

The class definitions for Robot and Robot2 are syntactically completely different, but they implement logically the same class.

What Python actually does in the first example, i.e. the "usual way" of defining classes, is the following: Python processes the complete class statement from class Robot to collect the methods and attributes of Robot to add them to the attributes_dict of the type call. So, Python will call type in a similar or the same way as we did in Robot2.

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